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2023-06-05 03:19:34 -07:00
# 1. Annotate the following python expressions with the specific types of each literal, as well as the overall return value:
# i = 3
# f = 3.0
# c = 3+3j
# b = b'abcdefg'
# s = 'abcdefg'
# s = "abcdefg"
i = 3
f = 3.0
c = 3+3j
b = b'abcdefg'
s1 = 'abcdefg'
s2 = "abcdefg"
def check_the_datatype():
print()
print('This is the answer for Q1:')
print()
variable_names = ['i', 'f', 'c', 'b', 's1', 's2']
data_list = [i, f, c, b, s1, s2]
for variable, data in zip(variable_names, data_list):
print("The type of this assigned value {} = {} is: {}".format(variable, data, type(data).__name__))
# 2. For each of the types string, bytestring, integer, floating point, and imaginary literals,
# construct a 5x5 table showing what happens when the character "0" or number 0 is compared to each other type
from tabulate import tabulate
from termcolor import colored
from tabulate import tabulate
from termcolor import colored
def tablesQ2():
print()
print('-' * 20)
print()
print('This is the answer for Q2:')
print()
types = ["String", "Byte String", "Integer", "Floating Point", "Imaginary"]
literals = ['"0"', 'b"0"', '0', '0.0', '0j']
table_data = []
for type_ in types:
row = [type_]
for literal in literals:
if type_ == "String":
result = literal == '"0"'
elif type_ == "Byte String":
result = literal.encode() == b"0"
elif type_ == "Integer":
try:
result = int(literal) == 0
except ValueError:
result = False
elif type_ == "Floating Point":
try:
result = float(literal) == 0.0
except ValueError:
result = False
elif type_ == "Imaginary":
result = literal.replace('j', 'j0') == "0j"
color = 'green' if result else 'red'
colored_result = colored(result, color)
row.append(colored_result)
table_data.append(row)
table = tabulate(table_data, headers=["Type"] + literals, tablefmt="pipe")
print(table)
# 3. Now do the same thing for the + and == operators for each pair of types in two other 5x5 tables.
def tablesQ3():
print()
print('-' * 20)
print()
print('This is the answer for Q3:')
print()
operators = ["+", "=="]
types = ["str", "bytes", "int", "float", "complex"]
literals = ['"0"', 'b"0"', '0', '0.0', '0+0j']
for operator in operators:
print(f"Table for {operator} Operator:")
table_data = []
for type_ in types:
row = [type_]
for literal in literals:
try:
result = eval(f"{literal} {operator} {type_}({literal})")
color = 'green'
except TypeError:
result = False
color = 'red'
colored_result = colored(result, color)
row.append(colored_result)
table_data.append(row)
table = tabulate(table_data, headers=["Type"] + literals, tablefmt="pipe")
print(table)
print()
# Write a small program that uses the AST module to open the lexer/parser example, and dumps the resulting AST.
# See if there are any arguments to the parse method which make the output easier to read.
# By default, ast.dump() prints the AST in a compact format.
# However, there are two optional arguments that can enhance the readability:
# indent: Specifies the number of spaces to use for indentation. Setting it to a positive integer (e.g., 4) indents each level of the AST by that amount.
# annotate_fields: When set to True, adds field names as comments to the output, making it easier to identify each part of the AST.
import ast
def dump_ast(filename):
with open(filename, 'r') as file:
source_code = file.read()
try:
tree = ast.parse(source_code)
ast_dump = ast.dump(tree, indent=4, annotate_fields=True)
print(ast_dump)
except SyntaxError as e:
print(f"Syntax error in {filename}: {e}")
if __name__ == "__main__":
check_the_datatype()
tablesQ2()
tablesQ3()
print()