Update page 'Solutions to the questions concerning R language'

xuanyi.wang
2023-05-22 20:54:18 +02:00
parent 324b9d87b3
commit 8e296c5640
@@ -7,4 +7,212 @@ set.seed(9004)
train = sample(dim(OJ)[1], 800)
OJ.train = OJ[train, ]
OJ.test = OJ[-train, ]
```
**ii.**
```
library(e1071)
```
```
## Warning: package 'e1071' was built under R version 3.0.2
```
```
## Loading required package: class
```
```
svm.linear = svm(Purchase ~ ., kernel = "linear", data = OJ.train, cost = 0.01)
summary(svm.linear)
```
```
##
## Call:
## svm(formula = Purchase ~ ., data = OJ.train, kernel = "linear",
## cost = 0.01)
##
##
## Parameters:
## SVM-Type: C-classification
## SVM-Kernel: linear
## cost: 0.01
## gamma: 0.05556
##
## Number of Support Vectors: 432
##
## ( 217 215 )
##
##
## Number of Classes: 2
##
## Levels:
## CH MM
```
Support vector classifier creates 432 support vectors out of 800 training points. Out of these, 217 belong to level 𝙲𝙷 and remaining 215 belong to level 𝙼𝙼.
**iii.**
```
train.pred = predict(svm.linear, OJ.train)
table(OJ.train$Purchase, train.pred)
```
```
## train.pred
## CH MM
## CH 439 53
## MM 82 226
```
```
(82 + 53)/(439 + 53 + 82 + 226)
```
```
## [1] 0.1688
```
```
test.pred = predict(svm.linear, OJ.test)
table(OJ.test$Purchase, test.pred)
```
```
## test.pred
## CH MM
## CH 142 19
## MM 29 80
```
```
(19 + 29)/(142 + 19 + 29 + 80)
```
```
## [1] 0.1778
```
The training error rate is 16.9% and test error rate is about 17.8%.
**iv.**
```
set.seed(1554)
tune.out = tune(svm, Purchase ~ ., data = OJ.train, kernel = "linear", ranges = list(cost = 10^seq(-2, 1, by = 0.25)))
summary(tune.out)
```
```
##
## Parameter tuning of 'svm':
##
## - sampling method: 10-fold cross validation
##
## - best parameters:
## cost
## 0.3162
##
## - best performance: 0.1687
##
## - Detailed performance results:
## cost error dispersion
## 1 0.01000 0.1688 0.03692
## 2 0.01778 0.1688 0.03398
## 3 0.03162 0.1713 0.03230
## 4 0.05623 0.1725 0.03162
## 5 0.10000 0.1700 0.03291
## 6 0.17783 0.1712 0.03336
## 7 0.31623 0.1687 0.03499
## 8 0.56234 0.1700 0.03129
## 9 1.00000 0.1687 0.03398
## 10 1.77828 0.1688 0.03241
## 11 3.16228 0.1688 0.03294
## 12 5.62341 0.1713 0.03121
## 13 10.00000 0.1713 0.03283
```
Tuning shows that optimal cost is 0.3162.
**v.**
```
svm.linear = svm(Purchase ~ ., kernel = "linear", data = OJ.train, cost = tune.out$best.parameters$cost)
train.pred = predict(svm.linear, OJ.train)
table(OJ.train$Purchase, train.pred)
```
```
## train.pred
## CH MM
## CH 435 57
## MM 71 237
```
```
(57 + 71)/(435 + 57 + 71 + 237)
```
```
## [1] 0.16
```
```
test.pred = predict(svm.linear, OJ.test)
table(OJ.test$Purchase, test.pred)
```
```
## test.pred
## CH MM
## CH 141 20
## MM 29 80
```
```
(29 + 20)/(141 + 20 + 29 + 80)
```
```
## [1] 0.1815
```
The training error decreases to 16% but test error slightly increases to 18.1% by using best cost.
**vi.**
```
set.seed(410)
svm.radial = svm(Purchase ~ ., data = OJ.train, kernel = "radial")
summary(svm.radial)
```
```
##
## Call:
## svm(formula = Purchase ~ ., data = OJ.train, kernel = "radial")
##
##
## Parameters:
## SVM-Type: C-classification
## SVM-Kernel: radial
## cost: 1
## gamma: 0.05556
##
## Number of Support Vectors: 367
##
## ( 184 183 )
##
##
## Number of Classes: 2
##
## Levels:
## CH MM
```
```
train.pred = predict(svm.radial, OJ.train)
table(OJ.train$Purchase, train.pred)
```
```
## train.pred
## CH MM
## CH 452 40
## MM 78 230
```
```
(40 + 78)/(452 + 40 + 78 + 230)
```
```
## [1] 0.1475
```
```
test.pred = predict(svm.radial, OJ.test)
table(OJ.test$Purchase, test.pred)
```
```
## test.pred
## CH MM
## CH 146 15
## MM 27 82
```
```
(27 + 15)/(146 + 15 + 27 + 82)
```
```
## [1] 0.1556
```