Update page 'Solutions to the questions concerning R language'

xuanyi.wang
2023-05-22 21:02:11 +02:00
parent 9ffbe9f1ae
commit 8230bd20bf
+205 -1
@@ -217,4 +217,208 @@ table(OJ.test$Purchase, test.pred)
## [1] 0.1556
```
The radial basis kernel with default gamma creates 367 support vectors, out of which, 184 belong to level `𝙲𝙷` and remaining 183 belong to level `𝙼𝙼`. The classifier has a training error of 14.7% and a test error of 15.6% which is a slight improvement over linear kernel. We now use cross validation to find optimal gamma.
```
set.seed(755)
tune.out = tune(svm, Purchase ~ ., data = OJ.train, kernel = "radial", ranges = list(cost = 10^seq(-2,
1, by = 0.25)))
summary(tune.out)
```
```
##
## Parameter tuning of 'svm':
##
## - sampling method: 10-fold cross validation
##
## - best parameters:
## cost
## 0.5623
##
## - best performance: 0.165
##
## - Detailed performance results:
## cost error dispersion
## 1 0.01000 0.3850 0.06258
## 2 0.01778 0.3850 0.06258
## 3 0.03162 0.3762 0.06908
## 4 0.05623 0.2100 0.03855
## 5 0.10000 0.1862 0.03143
## 6 0.17783 0.1837 0.03230
## 7 0.31623 0.1712 0.03438
## 8 0.56234 0.1650 0.03764
## 9 1.00000 0.1750 0.03584
## 10 1.77828 0.1738 0.04059
## 11 3.16228 0.1763 0.03748
## 12 5.62341 0.1763 0.03839
## 13 10.00000 0.1738 0.03459
```
```
svm.radial = svm(Purchase ~ ., data = OJ.train, kernel = "radial", cost = tune.out$best.parameters$cost)
train.pred = predict(svm.radial, OJ.train)
table(OJ.train$Purchase, train.pred)
```
```
## train.pred
## CH MM
## CH 452 40
## MM 77 231
```
```
(77 + 40)/(452 + 40 + 77 + 231)
```
```
## [1] 0.1462
```
```
test.pred = predict(svm.radial, OJ.test)
table(OJ.test$Purchase, test.pred)
```
```
## test.pred
## CH MM
## CH 146 15
## MM 28 81
```
```
(28 + 15)/(146 + 15 + 28 + 81)
```
```
## [1] 0.1593
```
Tuning slightly decreases training error to 14.6% and slightly increases test error to 16% which is still better than linear kernel.
**vii.**
```
set.seed(8112)
svm.poly = svm(Purchase ~ ., data = OJ.train, kernel = "poly", degree = 2)
summary(svm.poly)
```
```
##
## Call:
## svm(formula = Purchase ~ ., data = OJ.train, kernel = "poly",
## degree = 2)
##
##
## Parameters:
## SVM-Type: C-classification
## SVM-Kernel: polynomial
## cost: 1
## degree: 2
## gamma: 0.05556
## coef.0: 0
##
## Number of Support Vectors: 452
##
## ( 232 220 )
##
##
## Number of Classes: 2
##
## Levels:
## CH MM
```
```
train.pred = predict(svm.poly, OJ.train)
table(OJ.train$Purchase, train.pred)
```
```
## train.pred
## CH MM
## CH 460 32
## MM 105 203
```
```
(32 + 105)/(460 + 32 + 105 + 203)
```
```
## [1] 0.1713
```
```
test.pred = predict(svm.poly, OJ.test)
table(OJ.test$Purchase, test.pred)
```
```
## test.pred
## CH MM
## CH 149 12
## MM 37 72
```
```
(12 + 37)/(149 + 12 + 37 + 72)
```
```
## [1] 0.1815
```
Summary shows that polynomial kernel produces 452 support vectors, out of which, 232 belong to level 𝙲𝙷
and remaining 220 belong to level 𝙼𝙼
. This kernel produces a train error of 17.1
% and a test error of 18.1
% which are slightly higher than the errors produces by radial kernel but lower than the errors produced by linear kernel.
```
set.seed(322)
tune.out = tune(svm, Purchase ~ ., data = OJ.train, kernel = "poly", degree = 2, ranges = list(cost = 10^seq(-2, 1, by = 0.25)))
summary(tune.out)
```
```
##
## Parameter tuning of 'svm':
##
## - sampling method: 10-fold cross validation
##
## - best parameters:
## cost
## 5.623
##
## - best performance: 0.1837
##
## - Detailed performance results:
## cost error dispersion
## 1 0.01000 0.3850 0.05426
## 2 0.01778 0.3675 0.05076
## 3 0.03162 0.3575 0.05177
## 4 0.05623 0.3425 0.04937
## 5 0.10000 0.3150 0.05231
## 6 0.17783 0.2487 0.03929
## 7 0.31623 0.2088 0.05684
## 8 0.56234 0.2088 0.05653
## 9 1.00000 0.2000 0.06095
## 10 1.77828 0.1938 0.04497
## 11 3.16228 0.1862 0.04185
## 12 5.62341 0.1837 0.03336
## 13 10.00000 0.1837 0.04042
```
```
svm.poly = svm(Purchase ~ ., data = OJ.train, kernel = "poly", degree = 2, cost = tune.out$best.parameters$cost)
train.pred = predict(svm.poly, OJ.train)
table(OJ.train$Purchase, train.pred)
```
```
## train.pred
## CH MM
## CH 455 37
## MM 84 224
```
```
(37 + 84)/(455 + 37 + 84 + 224)
```
```
## [1] 0.1512
```
```
test.pred = predict(svm.poly, OJ.test)
table(OJ.test$Purchase, test.pred)
```
```
## test.pred
## CH MM
## CH 148 13
## MM 34 75
```
```
(13 + 34)/(148 + 13 + 34 + 75)
```
```
## [1] 0.1741
```